Firstly here's the England and Wales (UK except Scotland) holidays as an array in PHP called $holidays
$holidays2015=array("2015-12-24","2015-12-25","2015-12-28");
$holidays2016=array("2016-01-01","2016-03-25","2016-03-28","2016-05-02","2016-05-30","2016-08-29","2016-12-26","2016-12-27");
$holidays2017=array("2017-01-02","2017-04-14","2017-04-17","2017-05-01","2017-05-29","2017-08-28","2017-12-25","2017-12-26");
$holidays=array_merge($holidays2015,$holidays2016,$holidays2017);
Here's a function which also has an example. Originally posted by Dave
http://stackoverflow.com/users/4274143/dave
<?php
//The function returns the no. of business days between two dates and it skips the holidays
function getWorkingDays($startDate,$endDate,$holidays){
// do strtotime calculations just once
$endDate = strtotime($endDate);
$startDate = strtotime($startDate);
//The total number of days between the two dates. We compute the no. of seconds and divide it to 60*60*24
//We add one to inlude both dates in the interval.
$days = ($endDate - $startDate) / 86400 + 1;
$no_full_weeks = floor($days / 7);
$no_remaining_days = fmod($days, 7);
//It will return 1 if it's Monday,.. ,7 for Sunday
$the_first_day_of_week = date("N", $startDate);
$the_last_day_of_week = date("N", $endDate);
//---->The two can be equal in leap years when february has 29 days, the equal sign is added here
//In the first case the whole interval is within a week, in the second case the interval falls in two weeks.
if ($the_first_day_of_week <= $the_last_day_of_week) {
if ($the_first_day_of_week <= 6 && 6 <= $the_last_day_of_week) $no_remaining_days--;
if ($the_first_day_of_week <= 7 && 7 <= $the_last_day_of_week) $no_remaining_days--;
}
else {
// (edit by Tokes to fix an edge case where the start day was a Sunday
// and the end day was NOT a Saturday)
// the day of the week for start is later than the day of the week for end
if ($the_first_day_of_week == 7) {
// if the start date is a Sunday, then we definitely subtract 1 day
$no_remaining_days--;
if ($the_last_day_of_week == 6) {
// if the end date is a Saturday, then we subtract another day
$no_remaining_days--;
}
}
else {
// the start date was a Saturday (or earlier), and the end date was (Mon..Fri)
// so we skip an entire weekend and subtract 2 days
$no_remaining_days -= 2;
}
}
//The no. of business days is: (number of weeks between the two dates) * (5 working days) + the remainder
//---->february in none leap years gave a remainder of 0 but still calculated weekends between first and last day, this is one way to fix it
$workingDays = $no_full_weeks * 5;
if ($no_remaining_days > 0 )
{
$workingDays += $no_remaining_days;
}
//We subtract the holidays
foreach($holidays as $holiday){
$time_stamp=strtotime($holiday);
//If the holiday doesn't fall in weekend
if ($startDate <= $time_stamp && $time_stamp <= $endDate && date("N",$time_stamp) != 6 && date("N",$time_stamp) != 7)
$workingDays--;
}
return $workingDays;
}
//Example:
$holidays2015=array("2015-12-24","2015-12-25","2015-12-28");
$holidays2016=array("2016-01-01","2016-03-25","2016-03-28","2016-05-02","2016-05-30","2016-08-29","2016-12-26","2016-12-27");
$holidays2017=array("2017-01-02","2017-04-14","2017-04-17","2017-05-01","2017-05-29","2017-08-28","2017-12-25","2017-12-26");
$holidays=array_merge($holidays2015,$holidays2016,$holidays2017);
#echo getWorkingDays("2015-09-08","2015-09-10",$holidays);
// => will return 3
?>
